Question
18. The expression (e^2x-e^-2x)/(e^2x)+e^(-2x) is equivalent to __ A. 1 B. sinhx C. sinh2x D. tanh2x
Solution
4.4
(238 Votos)
Orlando
Elite · Tutor por 8 anos
Resposta
D
Explicação
The given expression is \((e^{2x}-e^{-2x})/(e^{2x}+e^{-2x})\). This expression is equivalent to the hyperbolic tangent function, denoted as \(tanh(x)\). Specifically, the expression is equivalent to \(tanh(2x)\). Therefore, the correct answer is option D:
.