Pergunta
![Suppose a point has polar coordinates (4,-(5pi )/(3)) with the angle measured in radians.
Find two additional polar representations of the point.
Write each coordinate In simplest form with the angle in [-2pi ,2pi ]
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Suppose a point has polar coordinates (4,-(5pi )/(3)) with the angle measured in radians. Find two additional polar representations of the point. Write each coordinate In simplest form with the angle in [-2pi ,2pi ] square
Solução

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ElisaVeterano · Tutor por 10 anos
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To find two additional polar representations of the point with polar coordinates (4,-\frac {5\pi }{3})
First, let's add 2\pi
-\frac {5\pi }{3} + 2\pi = -\frac {5\pi }{3} + \frac {6\pi }{3} = \frac {\pi }{3}
So, one additional polar representation of the point is (4,\frac {\pi }{3})
Next, let's subtract 2\pi
-\frac {5\pi }{3} - 2\pi = -\frac {5\pi }{3} - \frac {6\pi }{3} = -\frac {11\pi }{3}
Since the angle is negative, we can add 2\pi
-\frac {11\pi }{3} + 2\pi = -\frac {11\pi }{3} + \frac {6\pi }{3} = -\frac {5\pi }{3}
So, another additional polar representation of the point is (4,-\frac {5\pi }{3})
Therefore, the two additional polar representations of the point with polar coordinates (4,-\frac {5\pi }{3})
, we can add or subtract multiples of 2\pi
to the angle until it falls within the desired range of [-2\pi,2\pi ]
.
First, let's add 2\pi
to the angle:
-\frac {5\pi }{3} + 2\pi = -\frac {5\pi }{3} + \frac {6\pi }{3} = \frac {\pi }{3}
So, one additional polar representation of the point is (4,\frac {\pi }{3})
.
Next, let's subtract 2\pi
from the angle:
-\frac {5\pi }{3} - 2\pi = -\frac {5\pi }{3} - \frac {6\pi }{3} = -\frac {11\pi }{3}
Since the angle is negative, we can add 2\pi
to it until it falls within the desired range:
-\frac {11\pi }{3} + 2\pi = -\frac {11\pi }{3} + \frac {6\pi }{3} = -\frac {5\pi }{3}
So, another additional polar representation of the point is (4,-\frac {5\pi }{3})
.
Therefore, the two additional polar representations of the point with polar coordinates (4,-\frac {5\pi }{3})
are (4,\frac {\pi }{3})
and (4,-\frac {5\pi }{3})
.
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