Solve using substitution. 2x-10y=16 -3x+2y=15 square square

To solve the system of equations using substitution, we first solve one equation for one variable and then substitute that expression into the other equation.<br /><br />From the first equation, we can solve for $x$ in terms of $y$:<br />$2x - 10y = 16$<br />$2x = 10y + 16$<br />$x = 5y + 8$<br /><br />Now we substitute this expression for $x$ into the second equation:<br />$-3x + 2y = 15$<br />$-3(5y + 8) + 2y = 15$<br />$-15y - 24 + 2y = 15$<br />$-13y - 24 = 15$<br />$-13y = 39$<br />$y = -3$<br /><br />Now that we have found $y$, we can substitute it back into the expression for $x$:<br />$x = 5y + 8$<br />$x = 5(-3) + 8$<br />$x = -15 + 8$<br />$x = -7$<br /><br />Therefore, the solution to the system of equations is $x = -7$ and $y = -3$.