11. Write the Lewis dot structure for AsH_(3) by answering the following questions. a. What is the total number of valence electrons in the molecule? __ b. Which atom is at the center of the molecule? __ c. How many valence electrons do you have left? __ d. On which atom do the remaining two electrons go? __ e. Draw the lewis structure

a. The total number of valence electrons in the molecule can be calculated by adding the valence electrons of each atom. Arsenic (As) has 5 valence electrons, and hydrogen (H) has 1 valence electron. Since there are three hydrogen atoms, the total number of valence electrons in the molecule is 5 (from As) + 3 (from H) = 8.<br /><br />b. The central atom in the molecule is arsenic (As).<br /><br />c. After placing the central atom (As) in the center and connecting it to the surrounding atoms (H), we have used up 3 of the 8 valence electrons. Therefore, we have 8 - 3 = 5 valence electrons left.<br /><br />d. The remaining two electrons go on the hydrogen atom.<br /><br />e. The Lewis structure for $AsH_{3}$ is:<br /><br />```<br /> H<br /> |<br />H-As-H<br /> |<br /> H<br />```<br /><br />In this structure, arsenic (As) is at the center, with three hydrogen (H) atoms bonded to it. Each hydrogen atom has one lone pair of electrons, and arsenic has one lone pair of electrons.