Given the Balanced Reaction: 2Al2O3(l)arrow 4Al(s)+3O2(g) How many moles of O2 will be formed if 10 moles of A1203 are used? Choose matching detinition 15 moles of 02 10 moles of 02 5 moles of 02 20 moles of 02

To solve this problem, we need to use the stoichiometry of the balanced chemical equation.<br /><br />The balanced chemical equation is:<br />$2Al_2O_3(l) \rightarrow 4Al(s) + 3O_2(g)$<br /><br />From the equation, we can see that 2 moles of $Al_2O_3$ produce 3 moles of $O_2$.<br /><br />Given that 10 moles of $Al_2O_3$ are used, we can calculate the number of moles of $O_2$ formed as follows:<br /><br />Moles of $O_2$ = (3 moles of $O_2$ / 2 moles of $Al_2O_3$) × 10 moles of $Al_2O_3$<br />Moles of $O_2$ = 15 moles<br /><br />Therefore, the correct answer is:<br />15 moles of $O_2$