The following atoms all undergo beta decay. Write the complete nuclear equation. (}_{6)^14Carrow (}_{38)^90Srarrow (}_{19)^40Karrow (}_{7)^13Narrow

Beta decay is a type of radioactive decay in which a beta particle (an electron or a positron) is emitted from an unstable nucleus. In beta decay, a neutron is converted into a proton, and an electron (beta particle) is emitted. The nuclear equation for beta decay can be written as:<br /><br />${}_{Z}^{A}X\rightarrow {}_{Z+1}^{A}Y+{ }_{-1}^{0}e$<br /><br />Where:<br />- ${}_{Z}^{A}X$ represents the parent nucleus<br />- ${}_{Z+1}^{A}Y$ represents the daughter nucleus<br />- ${ }_{-1}^{0}e$ represents the emitted beta particle (electron)<br /><br />Let's write the complete nuclear equations for the given atoms:<br /><br />1. ${}_{6}^{14}C\rightarrow $<br />In this case, the parent nucleus is carbon-14 (${}_{6}^{14}C$). After beta decay, the daughter nucleus will have one more proton, so number will increase by 1. The mass number remains the same. Therefore, the complete nuclear equation is:<br /><br />${}_{6}^{14}C\rightarrow {}_{7}^{14}N+{ }_{-1}^{0}e$<br /><br />2. ${}_{38}^{90}Sr\rightarrow $<br />The parent nucleus is strontium-90 (${}_{38}^{90}Sr$). After beta decay, the daughter nucleus will have one more proton, so the atomic number will increase by 1. The mass number remains the same. Therefore, the complete nuclear equation is:<br /><br />${}_{38}^{90}Sr\rightarrow {}_{39}^{90}Y+{ }_{-1}^{0}e$<br /><br />3. ${}_{19}^{40}K\rightarrow $<br />The parent nucleus is potassium-40 (${}_{19}^{40}K$). After beta decay, the daughter nucleus will have one more proton, so the atomic number will increase by 1. The mass number remains the same. Therefore, the complete nuclear equation is:<br /><br />${}_{19}^{40}K\rightarrow {}_{20}^{40}Ca+{ }_{-1}^{0}e$<br /><br />4. ${}_{7}^{13}N\rightarrow $<br />The parent nucleus is nitrogen-13 (${}_{7}^{13}N$). After beta decay, the daughter nucleus will have one more proton, so the atomic number will increase by 1. The mass number remains the same. Therefore, the complete nuclear equation is:<br /><br />${}_{7}^{13}N\rightarrow {}_{8}^{13}O+{ }_{-1}^{0}e$<br /><br />These are the complete nuclear equations for the given atoms undergoing beta decay.