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1CuSO_(4)+2NaOH=1Na_(2)SO_(4)+1Cu(OH)_(2) QUESTIONS: 1) Cl_(2)+Kl=KCl+ldots I_(2) 3) KaCl_(3)+BnCl_(2)arrow KCl+BaCO_(3) 1) Na+NaCl_(2)Longrightarrow NaCl+ldots Mg a) Al+CuCl_(2)=-AlCl_(3)+Cu B) Al+ldots Vb(NO_(3))_(2)arrow Al(NO_(3))_(3)+ 6) AgNO_(3)+CaBraarrow AgBr+Ca(l) 7) Al_(2)(SO_(4))_(3)+Ca_(3)(PO_(4))_(2)arrow AlPO_(4)+ B) FeBr_(2)+K_(2)CO_(3)arrow KFCO_(3)+K 9) Cu+ldots Ag_(2)SO_(4)arrow ldots Ag+ldots CuSO ()) CuS+ldots KClarrow ldots CuCl_(2)+ldots K_(2)

Pergunta

1CuSO_(4)+2NaOH=1Na_(2)SO_(4)+1Cu(OH)_(2)
QUESTIONS:
1) Cl_(2)+Kl=KCl+ldots I_(2)
3) KaCl_(3)+BnCl_(2)arrow KCl+BaCO_(3)
1) Na+NaCl_(2)Longrightarrow NaCl+ldots Mg
a) Al+CuCl_(2)=-AlCl_(3)+Cu
B) Al+ldots Vb(NO_(3))_(2)arrow Al(NO_(3))_(3)+
6) AgNO_(3)+CaBraarrow AgBr+Ca(l)
7) Al_(2)(SO_(4))_(3)+Ca_(3)(PO_(4))_(2)arrow AlPO_(4)+
B) FeBr_(2)+K_(2)CO_(3)arrow KFCO_(3)+K
9) Cu+ldots Ag_(2)SO_(4)arrow ldots Ag+ldots CuSO
())
CuS+ldots KClarrow ldots CuCl_(2)+ldots K_(2)

1CuSO_(4)+2NaOH=1Na_(2)SO_(4)+1Cu(OH)_(2) QUESTIONS: 1) Cl_(2)+Kl=KCl+ldots I_(2) 3) KaCl_(3)+BnCl_(2)arrow KCl+BaCO_(3) 1) Na+NaCl_(2)Longrightarrow NaCl+ldots Mg a) Al+CuCl_(2)=-AlCl_(3)+Cu B) Al+ldots Vb(NO_(3))_(2)arrow Al(NO_(3))_(3)+ 6) AgNO_(3)+CaBraarrow AgBr+Ca(l) 7) Al_(2)(SO_(4))_(3)+Ca_(3)(PO_(4))_(2)arrow AlPO_(4)+ B) FeBr_(2)+K_(2)CO_(3)arrow KFCO_(3)+K 9) Cu+ldots Ag_(2)SO_(4)arrow ldots Ag+ldots CuSO ()) CuS+ldots KClarrow ldots CuCl_(2)+ldots K_(2)

Solução

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RobertaVeterano · Tutor por 11 anos

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1) $Cl_{2}+2KI=2KCl+I_{2}$<br />3) $K_{2}CO_{3}+BaCl_{2}\rightarrow 2KCl+BaCO_{3}$<br />1) $2Na+NaCl_{2}\Longrightarrow 3NaCl+Mg$<br />a) $2Al+3CuCl_{2}\rightarrow 2AlCl_{3}+3Cu$<br />B) $2Al+3Vb(NO_{3})_{2}\rightarrow 2Al(NO_{3})_{3}+3Vb$<br />6) $2AgNO_{3}+CaBr_{2}\rightarrow 2AgBr+Ca(NO_{3})_{2}$<br />7) $Al_{2}(SO_{4})_{3}+3Ca_{3}(PO_{4})_{2}\rightarrow 2AlPO_{4}+3CaSO_{4}$<br />B) $FeBr_{2}+3K_{2}CO_{3}\rightarrow 2KFeCO_{3}+3KBr$<br />9) $Cu+2Ag_{2}SO_{4}\rightarrow 2Ag+CuSO_{4}$<br />CuS+2KCl→CuCl_{2}+K_{2}S
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