Pergunta
+sqrt (5)-2sqrt [3](5)-7sqrt (5)=
f) 3sqrt (6)cdot (1+sqrt (6))=](https://static.questionai.br.com/resource%2Fqaiseoimg%2F202503%2F6-efetue-operaes-seguira-3sqrt-6sqrt-62sqrt-6sqrt-6dsqrt-tGaaZAVda100.jpg?x-oss-process=image/resize,w_558,h_500/quality,q_35/format,webp)
6- Efetue as operações a seguir: a) 3sqrt (6)+sqrt (6)-2sqrt (6)+sqrt (6)= d) sqrt (3)cdot sqrt (8)cdot sqrt (2)=sqrt (8) b) sqrt (8)+sqrt (50)-sqrt (128)+sqrt (18)= e) (10sqrt (27)+10sqrt (3)):10sqrt (3)= c) sqrt [3](5)+sqrt (5)-2sqrt [3](5)-7sqrt (5)= f) 3sqrt (6)cdot (1+sqrt (6))=
Solução

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SebastiãoProfissional · Tutor por 6 anos
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a) $3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt{6} + \sqrt{6} = 3\sqrt{6} + \sqrt{6} - 2\sqrt
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