MULTIPLE-CHOICE QUESTION If 20 moles of aluminum react, how many moles of Al_(2)S_(3) are produced? 16Al+3S_(8)- gt 8Al_(2)S_(3) 16 mol 2.5 mol 5 mol 10 mol

The balanced chemical equation given is \(16Al + 3S_8 \rightarrow 8Al_2S_3\). This equation tells us that 16 moles of aluminum (Al) react with 3 moles of sulfur (S_8) to produce 8 moles of aluminum sulfide (\(Al_2S_3\)).<br /><br />To find out how many moles of \(Al_2S_3\) are produced when 20 moles of aluminum react, we can set up a proportion based on the stoichiometry of the reaction:<br /><br />\[<br />\frac{16 \text{ moles of Al}}{8 \text{ moles of } Al_2S_3} = \frac{20 \text{ moles of Al}}{x \text{ moles of } Al_2S_3}<br />\]<br /><br />Solving for \([<br />x = \frac{20 \times 8}{16} = 10 \text{ moles of } Al_2S_3<br />\]<br /><br />Therefore, 10 moles of \(Al_2S_3\) are produced when 20 moles of aluminum react.