Balance the following chemical equation. When the equation is balanced, what is the coefficient found in front of the bold particle. found in the equation. PbCl_(2)+K_(2)SO_(4)arrow KCl+PbSO_(4) 4 1 0 2

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />The given equation is:<br />$PbCl_{2}+K_{2}SO_{4}\rightarrow KCl+PbSO_{4}$<br /><br />Let's balance the equation step by step:<br /><br />1. Balance the lead (Pb) atoms:<br /> $PbCl_{2}+K_{2}SO_{4}\rightarrow KCl+PbSO_{4}$<br /> There is 1 Pb atom on both sides, so the Pb atoms are already balanced.<br /><br />2. Balance the potassium (K) atoms:<br /> $PbCl_{2}+K_{2}SO_{4}\rightarrow KCl+PbSO_{4}$<br /> There are 2 K atoms on the left side and 1 K atom on the right side. To balance the K atoms, we need to put a coefficient of 2 in front of KCl on the right side:<br /> $PbCl_{2}+K_{2}SO_{4}\rightarrow 2KCl+PbSO_{4}$<br /><br />3. Balance the chlorine (Cl) atoms:<br /> $PbCl_{2}+K_{2}SO_{4}\rightarrow 2KCl+PbSO_{4}$<br /> There are 2 Cl atoms on the left side and 2 Cl atoms on the right side, so the Cl atoms are already balanced.<br /><br />4. Balance the sulfur (S) atoms:<br /> $PbCl_{2}+K_{2}SO_{4}\rightarrow 2KCl+PbSO_{4}$<br /> There is 1 S atom on both sides, so the S atoms are already balanced.<br /><br />The balanced chemical equation is:<br />$PbCl_{2}+K_{2}SO_{4}\rightarrow 2KCl+PbSO_{4}$<br /><br />The coefficient found in front of the bold particle (KCl) in the balanced equation is 2.