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Write a system of equations to describe the situation below,solve using any method, and fill in the blanks. Darrell and Zoe decided to shoot arrows at a simple target with a large outer ring and a smaller bull's-eye Darrell went first and landed 5 arrows in the outer ring and 4 arrows in the bull's-eye, for a total of 265 points. Zoe went second and got 5 arrows in the outer ring and 2 arrows in the bull's -eye, earning a total of 165 points How many points is each region of the target worth? The outer ring is worth square points, and the bull's-eye is worth square points.

Pergunta

Write a system of equations to describe the situation below,solve using any method, and fill
in the blanks.
Darrell and Zoe decided to shoot arrows at a simple target with a large outer ring and a
smaller bull's-eye Darrell went first and landed 5 arrows in the outer ring and 4 arrows in the
bull's-eye, for a total of 265 points. Zoe went second and got 5 arrows in the outer ring and 2
arrows in the bull's -eye, earning a total of 165 points How many points is each region of the
target worth?
The outer ring is worth square  points, and the bull's-eye is worth square  points.

Write a system of equations to describe the situation below,solve using any method, and fill in the blanks. Darrell and Zoe decided to shoot arrows at a simple target with a large outer ring and a smaller bull's-eye Darrell went first and landed 5 arrows in the outer ring and 4 arrows in the bull's-eye, for a total of 265 points. Zoe went second and got 5 arrows in the outer ring and 2 arrows in the bull's -eye, earning a total of 165 points How many points is each region of the target worth? The outer ring is worth square points, and the bull's-eye is worth square points.

Solução

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AuroraVeterano · Tutor por 10 anos

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Let's denote the points for the outer ring as
and the points for the bull's-eye as
. We can set up the following system of equations based on the information provided:

(Darrell's score)(Zoe's score)


To solve this system, we can use the elimination method. We can subtract the second equation from the first equation to eliminate
:



Simplifying the equation, we get:



Dividing both sides by 2, we find:



Now that we have the value of
, we can substitute it back into one of the original equations to solve for
. Let's use the second equation:



Simplifying the equation, we get:



Subtracting 100 from both sides, we have:



Dividing both sides by 5, we find:



Therefore, the outer ring is worth
points, and the bull's-eye is worth
points.
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