What is the pH of a solution with [H^+]=1.25times 10^-10 no Use pH=-log[H_(3)O^+] -10.1 -9.90 7.90 9.90

To find the pH of a solution with $$[H^{+}]=1.25\times 10^{-10}$$ , we can use the formula $$pH=-log[H_{3}O^{+}]$$ .

First, let's calculate the concentration of $$H_{3}O^{+}$$ , which is equal to the concentration of $$H^{+}$$ in this case.

Given that $$[H^{+}]=1.25\times 10^{-10}$$ , we can substitute this value into the formula:

$$pH = -log(1.25\times 10^{-10})$$

Using a calculator, we find that $$pH \approx 9.90$$ .

Therefore, the correct answer is 9.90.