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32) What is the name for FeO? a) Iron (1) oxide b) Iron oxide c) Iron monoxide d) Iron (II) oxide 33) What is the formula for Nickel (III) phosphide? a) Ni_(3)P b) Ni_(3)P_(3) c) NiP d) NiP_(3) 34) What is the formula for Manganese (IV) chlorate a) Mn_(4)Cl b) MnCl_(4) c) MnClO_(3) d) Mn(ClO_(3))_(4) 35) What is the formula for sodium monohydroger phosphate? a) Na_(2)HPO_(4) b) NaHPO_(2) c) Na_(3)HPO_(4) d) NaHPO_(4)

Pergunta

32) What is the name for FeO?
a) Iron (1) oxide
b) Iron oxide
c) Iron monoxide
d) Iron (II) oxide
33) What is the formula for Nickel
(III) phosphide?
a) Ni_(3)P
b) Ni_(3)P_(3)
c) NiP
d) NiP_(3)
34) What is the formula for Manganese (IV) chlorate
a) Mn_(4)Cl
b) MnCl_(4)
c) MnClO_(3)
d) Mn(ClO_(3))_(4)
35) What is the formula for sodium monohydroger phosphate?
a) Na_(2)HPO_(4)
b) NaHPO_(2)
c) Na_(3)HPO_(4)
d) NaHPO_(4)

32) What is the name for FeO? a) Iron (1) oxide b) Iron oxide c) Iron monoxide d) Iron (II) oxide 33) What is the formula for Nickel (III) phosphide? a) Ni_(3)P b) Ni_(3)P_(3) c) NiP d) NiP_(3) 34) What is the formula for Manganese (IV) chlorate a) Mn_(4)Cl b) MnCl_(4) c) MnClO_(3) d) Mn(ClO_(3))_(4) 35) What is the formula for sodium monohydroger phosphate? a) Na_(2)HPO_(4) b) NaHPO_(2) c) Na_(3)HPO_(4) d) NaHPO_(4)

Solução

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JulianaMestre · Tutor por 5 anos

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32) The correct answer is d) Iron (II) oxide. FeO represents iron with an oxidation state of +2, hence the (II) in the name.<br /><br />33) The correct answer is d) $NiP_{3}$. Nickel (III) indicates that nickel has an oxidation state of +3, and phosphide indicates the presence of phosphorus with an oxidation state of -3. Therefore, the formula is $NiP_{3}$.<br /><br />34) The correct answer is d) $Mn(ClO_{3})_{4}$. Manganese (IV) indicates that manganese has an oxidation state of +4, and chlorate is the polyatomic ion $ClO_{3}$. Therefore, the formula is $Mn(ClO_{3})_{4}$.<br /><br />35) The correct answer is d) $NaHPO_{4}$. Sodium monohydrogen phosphate is composed of sodium (Na), hydrogen (H), and the phosphate ion ($PO_{4}$). The correct formula is $NaHPO_{4}$.
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