13) AlBr_(3)+ldots K_(2)SO_(4)arrow ldots KBr+ldots Al_(2)(SO_(4))_(3) 14) 1-CH_(4)+2O_(2)arrow 1CO_(2)+2H_(2)O I 166

13) $AlBr_{3} + 3K_{2}SO_{4} \rightarrow 6KBr + Al_{2}(SO_{4})_{3}$<br /><br />14) $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$<br /><br />15) 151 ÷ 6 = 25.1667