11) How many grams are in 0.02 moles of beryllium iodide, BeI_(2) 12) How many moles are in 68 grams of copper (II) hydroxide, Cu(OH)_(2) 13) How many grams are in 3.3 moles of potassium sulfide. K_(2)S 14)How many moles are in 1.2times 10^3 grams of ammonia, NH_(3) 15) How many grams are in 2.3times 10^-4 moles of calcium phosphate, Ca_(3)(PO_(3))_(2) 16) How many moles are in 3.4times 10^-7 grams of silicon dioxide, SiO_(2)

11) To find the number of grams in 0.02 moles of beryllium iodide ($BeI_{2}$), we need to calculate the molar mass of $BeI_{2}$ first.<br /><br />The molar mass of $BeI_{2}$ is calculated as follows:<br />- Beryllium (Be): 9.01 g/mol<br />- Iodine (I): 126.90 g/mol<br /><br />Molar mass of $BeI_{2}$ = 9.01 g/mol + 2(126.90 g/mol) = 262.81 g/mol<br /><br />Now, we can calculate the number of grams in 0.02 moles of $BeI_{2}$:<br />Number of grams = Molar mass × Number of moles<br />Number of grams = 262.81 g/mol × 0.02 moles = 5.2562 grams<br /><br />Therefore, there are approximately 5.2562 grams in 0.02 moles of beryllium iodide ($BeI_{2}$).<br /><br />12) To find the number of moles in 68 grams of copper (II) hydroxide ($Cu(OH)_{2}$), we need to calculate the molar mass of $Cu(OH)_{2}$ first.<br /><br />The molar mass of $Cu(OH)_{2}$ is calculated as follows:<br />- Copper (Cu): 63.55 g/mol<br />- Oxygen (O): 16.00 g/mol<br />- Hydrogen (H): 1.01 g/mol<br /><br />Molar mass of $Cu(OH)_{2}$ = 63.55 g/mol + 2(16.00 g/mol + 1.01 g/mol) = 97.57 g/mol<br /><br />Now, we can calculate the number of moles in 68 grams of $Cu(OH)_{2}$:<br />Number of moles = Mass / Molar mass<br />Number of moles = 68 grams / 97.57 g/mol = 0.698 moles<br /><br />Therefore, there are approximately 0.698 moles in 68 grams of copper (II) hydroxide ($Cu(OH)_{2}$).<br /><br />13) To find the number of grams in 3.3 moles of potassium sulfide ($K_{2}S$), we need to calculate the molar mass of $K_{2}S$ first.<br /><br />The molar mass of $K_{2}S$ is calculated as follows:<br />- Potassium (K): 39.10 g/mol<br />- Sulfur (S): 32.07 g/mol<br /><br />Molar mass of $K_{2}S$ = 2(39.10 g/mol) + 32.07 g/mol = 110.27 g/mol<br /><br />Now, we can calculate the number of grams in 3.3 moles of $K_{2}S$:<br />Number of grams = Molar mass × Number of moles<br />Number of grams = 110.27 g/mol × 3.3 moles = 364.89 grams<br /><br />Therefore, there are approximately 364.89 grams in 3.3 moles of potassium sulfide ($K_{2}S$).<br /><br />14) To find the number of moles in $1.2\times 10^{3}$ grams of ammonia ($NH_{3}$), we need to calculate the molar mass of $NH_{3}$ first.<br /><br />The molar mass of $NH_{3}$ is calculated as follows:<br />- Nitrogen (N): 14.01 g/mol<br />- Hydrogen (H): 1.01 g/mol<br /><br />Molar mass of $NH_{3}$ = 14.01 g/mol + 3(1.01 g/mol) = 17.04 g/mol<br /><br />Now, we can calculate the number of moles in $1.2\times 10^{3}$ grams of $NH_{3}$:<br />Number of moles = Mass / Molar mass<br />Number of moles = $1.2\times 10^{3}$ grams / 17.04 g/mol = 70.59 moles<br /><br />Therefore, there are approximately 70.59 moles in $1.2\times 10^{3}$ grams of ammonia ($NH_{3}$).<br /><br />15) To find the number of grams in $2.3\times 10^{-4}$ moles of calcium phosphate ($Ca_{3}(PO_{3})_{2}$), we need to calculate the molar mass of $Ca_{3}(PO_{3})_{2}$ first.<br /><br />The molar mass of $Ca_{3}(PO_{3})_{2}$ is calculated as follows:<br />- Calcium (Ca): 40.08 g/mol<br />- Phosphorus (P): 30.97 g/mol<br />- Oxygen (O): 16.00 g/mol<br /><br />Molar mass