For every 9 moles of FeO there are how many moles of Al. "Note the equation has already been balanced for you. 2Al+3FeOarrow Al_(2)O_(3)+3Fe A 10 moles B 6 moles C 3 moles D 1 mole

## Step 1
The given chemical equation is $2Al + 3FeO \rightarrow Al_{2}O_{3} + 3Fe$. This equation tells us that 2 moles of Aluminum (Al) react with 3 moles of Iron(II) oxide (FeO) to produce 1 mole of Aluminum oxide (Al_{2}O_{3}) and 3 moles of Iron (Fe).

## Step 2
The problem asks us to find out how many moles of Aluminum (Al) are present for every 9 moles of Iron(II) oxide (FeO).

## Step 3
We can set up a proportion to solve this. The proportion is $\frac{2 \text{ moles of Al}}{3 \text{ moles of FeO}} = \frac{x \text{ moles of Al}}{9 \text{ moles of FeO}}$, where x is the number of moles of Aluminum (Al).

## Step 4
Solving the proportion for x gives us the number of moles of Aluminum (Al) for every 9 moles of Iron(II) oxide (FeO).