Pergunta
10. Phenyl magnesium bromide is used as a Grighard reagent is organic synthesis. Determine its empirical and molecular formula if its mouler mans is 181.319 ginool and it contains 39.7458% c. 2.77956% 13.4059% Mr. and 4600919686
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Olivia MariaProfissional · Tutor por 6 anos
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To determine the empirical and molecular formula of phenyl magnesium bromide, we need to follow these steps:<br /><br />1. Calculate the percentage composition of each element in the compound.<br />2. Convert the percentage composition to grams.<br />3. Determine the simplest whole number ratio of the elements.<br />4. Write the empirical formula based on the simplest whole number ratio.<br />5. Calculate the molar mass of the empirical formula.<br />6. Determine the molecular formula based on the given molar mass.<br /><br />Given information:<br />- Molar mass of phenyl magnesium bromide: 181.319 g/mol<br />- Percentage composition: C: 39.7458%, H: 2.77956%, Br: 13.4059%, Mg: 43.8886%<br /><br />Step 1: Calculate the percentage composition of each element in the compound.<br />Percentage composition:<br />- C: 39.7458%<br />- H: 2.77956%<br />- Br: 13.4059%<br />- Mg: 43.8886%<br /><br />Step 2: Convert the percentage composition to grams.<br />Assume we have 100 g of the compound.<br />- C: 39.7458 g<br />- H: 2.77956 g<br />- Br: 13.4059 g<br />- Mg: 43.8886 g<br /><br />Step 3: Determine the simplest whole number ratio of the elements.<br />Divide each mass by the smallest mass (H: 2.77956 g) to get the simplest whole number ratio.<br />- C: 39.7458 g / 2.77956 g = 14.29<br />- H: 2.77956 g / 2.77956 g = 1<br />- Br: 13.4059 g / 2.77956 g = 4.83<br />- Mg: 43.8886 g / 2.77956 g = 15.83<br /><br />The simplest whole number ratio is approximately 14:1:5:16.<br /><br />Step 4: Write the empirical formula based on the simplest whole number ratio.<br />Empirical formula: C14HBr5Mg<br /><br />Step 5: Calculate the molar mass of the empirical formula.<br />Molar mass of C14HBr5Mg = (14 × 12.01) + (1 × 1.008) + (5 × 79.904) + (1 × 24.305) = 341.36 g/mol<br /><br />Step 6: Determine the molecular formula based on the given molar mass.<br />Given molar mass of phenyl magnesium bromide: 181.319 g/mol<br />Molecular formula: (C14HBr5Mg)2 = C28H2Br10Mg2<br /><br />Therefore, the empirical formula of phenyl magnesium bromide is C14HBr5Mg, and the molecular formula is C28H2Br10Mg2.
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