Divide: (z^12)/(z^-4) z^3 z^6 z^8 z^16

To solve the division problem \(\frac{z^{12}}{z^{-4}}\), we use the property of exponents that states:<br /><br />\[<br />\frac{a^m}{a^n} = a^{m-n}<br />\]<br /><br />Applying this rule to the given expression:<br /><br />\[<br />\frac{z^{12}}{z^{-4}} = z^{12 - (-4)} = z^{12 + 4} = z^{16}<br />\]<br /><br />Therefore, the correct answer is \( z^{16} \).