Pergunta
E85b (7) (5)/(7)+3= (8) (1)/(9)+2(7)/(15)= (9) 1(5)/(12)+2(7)/(18)= (10) (1)/(6)+(5)/(22)= (II) 3(9)/(14)+4(15)/(28)=
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DelmaProfissional · Tutor por 6 anos
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(7) \frac{5}{7} + 3 = \frac{5}{7} + \frac{21}{7} = \frac{26}{7} = 3\frac{5}{7}
(8) \frac{1}{9} + 2\frac{7}{15} = \frac{1}{9} + \frac{37}{15} = \frac{15}{135} + \frac{111}{135} = \frac{226}{135} = 1\frac{91}{135}
(9) 1\frac{5}{12} + 2\frac{7}{18} = \frac{17}{12} + \frac{37}{18} = \frac{51}{36} + \frac{74}{36} = \frac{125}{36} = 3\frac{17}{36}
(10) \frac{1}{6} + \frac{5}{22} = \frac{11}{66} + \frac{15}{66} = \frac{26}{66} = \frac{13}{33}
(II) 3\frac{9}{14} + 4\frac{15}{28} = \frac{57}{14} + \frac{93}{28} = \frac{114}{28} + \frac{93}{28} = \frac{207}{28} = 7\frac{11}{28}
(8) \frac{1}{9} + 2\frac{7}{15} = \frac{1}{9} + \frac{37}{15} = \frac{15}{135} + \frac{111}{135} = \frac{226}{135} = 1\frac{91}{135}
(9) 1\frac{5}{12} + 2\frac{7}{18} = \frac{17}{12} + \frac{37}{18} = \frac{51}{36} + \frac{74}{36} = \frac{125}{36} = 3\frac{17}{36}
(10) \frac{1}{6} + \frac{5}{22} = \frac{11}{66} + \frac{15}{66} = \frac{26}{66} = \frac{13}{33}
(II) 3\frac{9}{14} + 4\frac{15}{28} = \frac{57}{14} + \frac{93}{28} = \frac{114}{28} + \frac{93}{28} = \frac{207}{28} = 7\frac{11}{28}
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