Pergunta
Assume the following situation can be modeled by a linear function. Write an equation for the linear function and use it to answer the given question. Be sure you clearly identify the independent and dependent variables. Then briefly discuss whether a linear model is reasonable for the situation described. The price of a particular model car is 17,000 today and rises with time at a constant rate of 880 per year. How much will a new car of this mode cost in 3.6 years? (Simplify your answer.) A. The independent variable is time (t), in years and the dependent variable is the price (p).in dollars. The linear function that models this situation is p=17000+(880times t) B. The independent variable is the price (p).in dollars, and the dependent variable is time (t), in years. The linear function that models this situation is t=square The price of a car after 3.6 years will be s (Simplify your answer.)
Solução
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RodrigoEspecialista · Tutor por 3 anos
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A. The independent variable is time (t), in years, and the dependent variable is the price (p) in dollars. The linear function that models this situation is \(p = 17000 + 880t\).<br />B. The price of a car after 3.6 years will be \(p = 17000 + 880*3.6 = 19776\).
Explicação
## Step 1<br />The problem involves a linear function, which is a function of the form \(y = mx + b\), where \(m\) is the slope (rate of change) and \(b\) is the y-intercept (initial value).<br /><br />## Step 2<br />In this case, the price of the car is the dependent variable (y), which depends on the time (t), the independent variable (x). The initial price of the car (when \(t = 0\)) is $17,000, which is the y-intercept (b). The price increases by $880 per year, which is the slope (m).<br /><br />## Step 3<br />The linear function that models this situation is \(p = 17000 + 880t\).<br /><br />## Step 4<br />To find the price of the car after 3.6 years, we substitute \(t = 3.6\) into the equation.
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