What value is a solution to two of the equations? (p)/(2)+4=10 2=10-delta h 3y-16=20 24 8 12 19

To find the value of a solution to two of the equations, we need to solve each equation separately and then compare the solutions.<br /><br />Let's start with the first equation:<br />$\frac {p}{2}+4=10$<br /><br />To solve for p, we need to isolate p on one side of the equation. We can do this by subtracting 4 from both sides:<br />$\frac {p}{2}=6$<br /><br />Now, we can multiply both sides by 2 to solve for p:<br />$p=12$<br /><br />Next, let's solve the third equation:<br />$3y-16=20$<br /><br />To solve for y, we need to isolate y on one side of the equation. We can do this by adding 16 to both sides:<br />$3y=36$<br /><br />Now, we can divide both sides by 3 to solve for y:<br />$y=12$<br /><br />Comparing the solutions, we can see that the value of a solution to two of the equations is 12.<br /><br />Therefore, the correct answer is 12.