Let f(x)=4x^2+2 and g(x)=-2x+3 Find the following. (f-g)(-4) (f-g)(-4)= square

To find $(f-g)(-4)$, we need to evaluate the functions $f(x)$ and $g(x)$ at $x=-4$ and then subtract the result of $g(x)$ from $f(x)$.<br /><br />Step 1: Evaluate $f(-4)$<br />$f(-4) = 4(-4)^{2}+2 = 4(16)+2 = 64+2 = 66$<br /><br />Step 2: Evaluate $g(-4)$<br />$g(-4) = -2(-4)+3 = 8+3 = 11$<br /><br />Step 3: Subtract $g(-4)$ from $f(-4)$<br />$(f-g)(-4) = f(-4) - g(-4) = 66 - 11 = 55$<br /><br />Therefore, $(f-g)(-4) = 55$.