__ 19. Are the lines y=-x-2 and 4x+4y=16 Explain A. Yes; their alopes have product -1 B. No_(2) their alopen are not opposite reciprocals C. Yes; their slopes are equal D. No; their alopes are not equal

To determine if the lines $y=-x-2$ and $4x+4y=16$ are perpendicular, we need to find their slopes and check if their product is -1.<br /><br />The slope of the first line $y=-x-2$ is -1. We can find this by rewriting the equation in slope-intercept form $y=mx+b$, where $m$ is the slope. In this case, the slope is -1.<br /><br />The slope of the second line $4x+4y=16$ can be found by rearranging the equation to solve for $y$. We have $4y=-4x+16$, which simplifies to $y=-x+4$. The slope of this line is also -1.<br /><br />Since the product of the slopes is $(-1) \times (-1) = 1$, the lines are not perpendicular. Therefore, the correct answer is:<br /><br />D. No; their slopes are not equal.