b. Solve the given s 4x-4y=20 3x-4y=15

To solve the given system of equations, we can use the method of elimination. <br /><br />The given system of equations is:<br />$4x - 4y = 20$<br />$3x - 4y = 15$<br /><br />Step 1: Subtract the second equation from the first equation to eliminate the $y$ term.<br />$(4x - 4y) - (3x - 4y) = 20 - 15$<br />$4x - 4y - 3x + 4y = 5$<br />$x = 5$<br /><br />Step 2: Substitute the value of $x$ into one of the original equations to find the value of $y$.<br />Let's substitute $x = 5$ into the first equation:<br />$4(5) - 4y = 20$<br />$20 - 4y = 20$<br />$-4y = 0$<br />$y = 0$<br /><br />Therefore, the solution to the given system of equations is $x = 5$ and $y = 0$.