Find the product. Write your answer in standard form. (n+3)^2 u

To find the product of \((n+3)^2\), we can use the binomial theorem or simply expand it by multiplying the binomial by itself.<br /><br />\[<br />(n+3)^2 = (n+3)(n+3)<br />\]<br /><br />Now, apply the distributive property (FOIL method):<br /><br />1. First: \( n \cdot n = n^2 \)<br />2. Outer: \( n \cdot 3 = 3n \)<br />3. Inner: \( 3 \cdot n = 3n \)<br />4. Last: \( 3 \cdot 3 = 9 \)<br /><br />Combine all the terms:<br /><br />\[<br />n^2 + 3n + 3n + 9<br />\]<br /><br />Combine like terms:<br /><br />\[<br />n^2 + 6n + 9<br />\]<br /><br />So, the product in standard form is:<br /><br />\[<br />\boxed{n^2 + 6n + 9}<br />\]