Questão 41. Se x=9log_(120)2+3log_(120)3+2log_(14400)125 podemos afirmar que x=2 B ( ( )x=3 ( )x=4 D ( )x=5 El ( )x=6

Para resolver essa questão, vamos simplificar a expressão dada para encontrar o valor de x.<br /><br />Dado que:<br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />Podemos reescrever a expressão usando as propriedades dos logaritmos:<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log00}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3 + 2\log_{14400}125$<br /><br />$x = 9\log_{120}2 + 3\log_{120}3