A bag contains 4 red marbles, 3 blue marbles and 6 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be red? Answer Attemptiout of 2 square

To find the probability of drawing 3 red marbles from the bag, we need to calculate the total number of ways to draw 3 marbles from the bag and the number of ways to draw 3 red marbles from the bag.<br /><br />The total number of marbles in the bag is 4 red + 3 blue + 6 green = 13 marbles.<br /><br />The number of ways to draw 3 marbles from the bag is given by the combination formula: C(n, k) = n! / (k!(n-k)!), where n is the total number of items and k is the number of items to choose.<br /><br />C(13, 3) = 13! / (3!(13-3)!) = 286<br /><br />The number of ways to draw 3 red marbles from the bag is given by the combination formula: C(4, 3) = 4! / (3!(4-3)!) = 4<br /><br />Therefore, the probability of drawing 3 red marbles from the bag is:<br /><br />P(3 red) = C(4, 3) / C(13, 3) = 4 / 286 = 2 / 143<br /><br />So, the exact probability that all three marbles drawn will be red is 2/143.