If Delta ABC is a right triangle where a and b are the legs and c is the hypotenuse, then a^2+b^2=c^2 ((x_(1)+x_(2))/(2),(y_(1)+y_(2))/(2)) d=sqrt ((x_(2)-x_(1))^2+(y_(2)-y_(1))^2) (1) Find b. (2) Divide by 2. (3) Square it. (4) This is the constant term of the quadratic. a set of all points in a plane that are the same distance from a given point, called the center (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius the segment whose endpoints are the center of the circle and a point on the circle the chord that passes through the center of

(1) To find b, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). So, we can rearrange the equation to solve for b:<br /><br />$a^{2}+b^{2}=c^{2}$<br />$b^{2}=c^{2}-a^{2}$<br />$b=\sqrt{c^{2}-a^{2}}$<br /><br />(2) To divide b by 2, we simply divide the expression for b by 2:<br /><br />$b/2=\frac{\sqrt{c^{2}-a^{2}}}{2}$<br /><br />(3) To square b/2, we simply square the expression for b/2:<br /><br />$(b/2)^{2}=\left(\frac{\sqrt{c^{2}-a^{2}}}{2}\right)^{2}=\frac{c^{2}-a^{2}}{4}$<br /><br />(4) The constant term of the quadratic equation is the term that does not contain any variables. In this case, the constant term is $\frac{c^{2}-a^{2}}{4}$.<br /><br />The set of all points in a plane that are the same distance from a given point, called the center, is called a circle. The equation of a circle with center $(h,k)$ and radius $r$ is given by:<br /><br />$(x-h)^{2}+(y-k)^{2}=r^{2}$<br /><br />The segment whose endpoints are the center of the circle and a point on the circle is called the radius of the circle.<br /><br />The chord that passes through the center of the circle is called the diameter of the circle.