14) f(x)=3x-2 g(x)=x-3 Fin d (fcirc g)(x)

To find $(f\circ g)(x)$, we need to substitute $g(x)$ into $f(x)$.<br /><br />Given:<br />$f(x) = 3x - 2$<br />$g(x) = x - 3$<br /><br />Substitute $g(x)$ into $f(x)$:<br />$(f\circ g)(x) = f(g(x)) = f(x-3)$<br /><br />Now, substitute $x-3$ into $f(x)$:<br />$(f\circ g)(x) = 3(x-3) - 2$<br /><br />Simplify the expression:<br />$(f\circ g)(x) = 3x - 9 - 2$<br />$(f\circ g)(x) = 3x - 11$<br /><br />Therefore, $(f\circ g)(x) = 3x - 11$.