The equation for line k can be written as y+5= (7)/(5)(x-10) . Line l is parallel to line k and passes through (-3,-6) . What is the equation of line l? Write the equation in tercept form . Write the numbers in the equatior as simplified proper fractions , improper fractions, or integers. square

To find the equation of line l, we need to use the fact that parallel lines have the same slope. The slope of line k can be found by looking at the coefficient of (x-10) in the equation for line k.<br /><br />The equation for line k is given as:<br />$y + 5 = \frac{7}{5}(x - 10)$<br /><br />Comparing this with the point-slope form of a linear equation, which is $y - y_1 = m(x - x_1)$, we can see that the slope of line k is $\frac{7}{5}$.<br /><br />Since line l is parallel to line k, it will have the same slope. Therefore, the slope of line l is also $\frac{7}{5}$.<br /><br />Now, we can use the point-slope form of a linear equation to find the equation of line l. We know that line l passes through the point (-3, -6), so we can substitute these values into the point-slope form:<br /><br />$y - (-6) = \frac{7}{5}(x - (-3))$<br /><br />Simplifying this equation gives us:<br /><br />$y + 6 = \frac{7}{5}(x + 3)$<br /><br />Therefore, the equation of line l in intercept form is:<br />$y + 6 = \frac{7}{5}(x + 3)$