Question 10 (Multiple (07.02 LC) Factor completely 3ab(x+1)-2(x+1) Prime (x+1)(3ab+2) (x+1)(3ab-2) (x+1)(ab)

## Step 1<br />The given expression is \(3ab(x+1)-2(x+1)\). We can see that both terms have a common factor of \((x+1)\).<br /><br />## Step 2<br />We can factor out the common factor \((x+1)\) from both terms. This is done by dividing each term by the common factor.<br /><br />### \(3ab(x+1)-2(x+1) = (x+1)(3ab-2)\)