Question 8 (2 points) What are the roots to the following equation? (x+4)^2=25 a 1 b -29 C -9,1 d 9,-1

To find the roots of the equation $(x+4)^{2}=25$, we need to solve for x.<br /><br />Step 1: Take the square root of both sides of the equation.<br />$\sqrt{(x+4)^{2}} = \sqrt{25}$<br />$x+4 = \pm 5$<br /><br />Step 2: Solve for x.<br />$x+4 = 5$ or $x+4 = -5$<br />$x = 1$ or $x = -9$<br /><br />Therefore, the roots of the equation are $\{ -9,1\}$.<br /><br />Answer: C $\{ -9,1\}$