The movement of the progress bar may be uneven because ql questions can be worth more or less (including zero)depending on your answer. In 2009, the world's largest pumpkin weighed 784 kilograms. An average-sized pumpkin weighs 5, 000 grams. The 2009 world-record pumpkin weighs __ kilograms more than an average-sized pumpkin. (Write your answer as a numeral.) The solution is square

## Step 1<br />The problem provides the the world's largest pumpkin in 2009, which is 784 kilograms. It also provides the weight of an average-sized pumpkin, which is 5,000 grams. However, the weights are not in the same unit, so we need to convert the weight of the average-sized pumpkin to kilograms.<br />### **1 kilogram = 1000 grams**<br />## Step 2<br />To convert the weight of the average-sized pumpkin from grams to kilograms, we divide the weight in grams by 1000.<br />### **Weight in kilograms = \(\frac{Weight\,in\,grams}{1000}\)**<br />## Step 3<br />Substitute the given weight of the average-sized pumpkin (5000 grams) into the formula.<br />### **Weight in kilograms = \(\frac{5000}{1000} = 5\) kilograms**<br />## Step 4<br />Now that we have the weights of both the world's largest pumpkin and an average-sized pumpkin in the same unit (kilograms), we can find the difference by subtracting the weight of the average-sized pumpkin from the weight of the world's largest pumpkin.<br />### **Difference in weight = Weight of world's largest pumpkin - Weight of average-sized pumpkin**<br />## Step 5<br />Substitute the given weights into the formula.<br />### **Difference in weight = 784 kilograms - 5 kilograms = 779 kilograms**