Which of the following correctly demonstrates the use of the Co Commutative Property of Multiplication? A 3(b^10+4)=3(4+b^10)3 B 11(b+z)=11b+11z C 2(b^10+z^11)=(b^10+z^11)cdot 2 D z^11cdot 2=z^11+2 A B C D

The Commutative Property of Multiplication states that the order in which two numbers are multiplied does not affect the product. In other words, for any two numbers a and b, a * b = b * a.<br /><br />Let's analyze each option:<br /><br />A. $3(b^{10}+4)=3(4+b^{10})$<br />This expression demonstrates the Commutative Property of Addition, not Multiplication. The terms within the parentheses are rearranged, but the multiplication remains the same.<br /><br />B. $11(b+z)=11b+11z$<br />This expression demonstrates the Distributive Property, not the Commutative Property of Multiplication.<br /><br />C. $2(b^{10}+z^{11})=(b^{10}+z^{11})\cdot 2$<br />This expression demonstrates the Commutative Property of Multiplication. The order of the factors is changed, but the product remains the same.<br /><br />D. $z^{11}\cdot 2=z^{11}+2$<br />This expression demonstrates the Commutative Property of Addition, not Multiplication. The terms within the parentheses are rearranged, but the multiplication remains the same.<br /><br />Therefore, the correct answer is C.