1) Faça a racionalização das seguintes expressões: a) (3)/(sqrt (2))= b) (8)/(sqrt (2))= c) (sqrt (5))/(sqrt (5))= d) (3sqrt (6))/(sqrt (3))= e) (4-sqrt (3))/(sqrt (2))= f) (sqrt (3))/(2sqrt (5))= g) (sqrt (2))/(3sqrt (3))= h) (sqrt (7))/(2sqrt (3))= i) (2+sqrt (2))/(sqrt (2))= j) (5-sqrt (2))/(sqrt (3))= k) (4)/(2+sqrt (2))= I) (5)/(6-sqrt (3))= m) (4)/(sqrt (2)-6)= n) (2)/(5-sqrt (3))= o) (7)/(sqrt (3)-sqrt (2))= p) (9)/(sqrt (3)+1)= q) (sqrt (3))/(sqrt (7)+sqrt (3))=

a) $$\frac {3}{\sqrt {2}} = \frac {3\sqrt {2}}{2}$$
b) $$\frac {8}{\sqrt {2}} = 4\sqrt {2}$$
c) $$\frac {\sqrt {5}}{\sqrt {5}} = 1$$
d) $$\frac {3\sqrt {6}}{\sqrt {3}} = 3\sqrt {2}$$
e) $$\frac {4-\sqrt {3}}{\sqrt {2}} = \frac {4\sqrt {2}-\sqrt {6}}{2}$$
f) $$\frac {\sqrt {3}}{2\sqrt {5}} = \frac {\sqrt {15}}{10}$$
g) $$\frac {\sqrt {2}}{3\sqrt {3}} = \frac {\sqrt {6}}{9}$$
h) $$\frac {\sqrt {7}}{2\sqrt {3}} = \frac {\sqrt {21}}{6}$$
i) $$\frac {2+\sqrt {2}}{\sqrt {2}} = 2\sqrt {2}+2$$
j) $$\frac {5-\sqrt {2}}{\sqrt {3}} = \frac {5\sqrt {3}-\sqrt {6}}{3}$$
k) $$\frac {4}{2+\sqrt {2}} = 2-\sqrt {2}$$
l) $$\frac {5}{6-\sqrt {3}} = \frac {5(6+\sqrt {3})}{33}$$
m) $$\frac {4}{\sqrt {2}-6} = \frac {4(\sqrt {2}+6)}{34}$$
n) $$\frac {2}{5-\sqrt {3}} = \frac {2(5+\sqrt {3})}{22}$$
o) $$\frac {7}{\sqrt {3}-\sqrt {2}} = \frac {7(\sqrt {3}+\sqrt {2})}{1}$$
p) $$\frac {9}{\sqrt {3}+1} = \frac {9(\sqrt {3}-1)}{2}$$
q) $$\frac {\sqrt {3}}{\sqrt {7}+\sqrt {3}} = \frac {\sqrt {21}-\sqrt {3}}{4}$$