Function g is defined as g(x)=2x^2+5x-1 What are the solutions to g(x)=0 A x=(-5pm sqrt (33))/(4) (i) I x=(-5pm sqrt (17))/(4) C x=(5pm sqrt (33))/(4) D x=(5pm sqrt (17))/(4)

To find the solutions to the equation $$g(x)=0$$ , we need to solve the quadratic equation $$2x^2 + 5x - 1 = 0$$ .

We can use the quadratic formula to solve this equation. The quadratic formula is given by:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

In this case, $$a = 2$$ , $$b = 5$$ , and $$c = -1$$ . Plugging these values into the quadratic formula, we get:

$$x = \frac{-5 \pm \sqrt{5^2 - 4(2)(-1)}}{2(2)}$$

Simplifying further, we have:

$$x = \frac{-5 \pm \sqrt{25 + 8}}{4}$$

$$x = \frac{-5 \pm \sqrt{33}}{4}$$

Therefore, the solutions to the equation $$g(x)=0$$ are:

$$x = \frac{-5 \pm \sqrt{33}}{4}$$

So, the correct answer is option A.