In a certain country the true probability of a baby being a boy is 0.538. Among the next nine randomly selected births in the country.what is the probability that at least one of them is a girl? The probability is square (Round to three decimal places as needed.)

To solve this problem, we can use the concept of complementary probability.

Given information:
- The true probability of a baby being a boy is 0.538.
- We need to find the probability that at least one of the next nine randomly selected births is a girl.

Step 1: Calculate the probability of a baby being a girl.
Probability of a baby being a girl = 1 - Probability of a baby being a boy
Probability of a baby being a girl = 1 - 0.538 = 0.462

Step 2: Calculate the probability of all nine babies being boys.
Probability of all nine babies being boys = (Probability of a baby being a boy)^9
Probability of all nine babies being boys = (0.538)^9 = 0.002

Step 3: Calculate the probability of at least one baby being a girl.
Probability of at least one baby being a girl = 1 - Probability of all nine babies being boys
Probability of at least one baby being a girl = 1 - 0.002 = 0.998

Therefore, the probability that at least one of the next nine randomly selected births is a girl is 0.998 (rounded to three decimal places).