Pergunta

3) Determine o valor das expressões dadas,apresentando o resultado em notação científica (Multiplicação e Divisão). a) 2,0times 10^8cdot 3,0times 10^9= (9,0times 10^9cdot 6,0times 10^-6)/(3,0times 10^-3)= b) 3,5times 10^-15cdot 4,0times 10^5= c) 8.9,0times 10^-19= h) (9,0times 10^9cdot 6,0times 10^-6cdot 2,0times 10^-6)/(3,0times 10^-5)= d) 2,0times 10^8cdot (-2,0times 10^19)cdot (4,5times 10^-15)= i) (9,0times 10^9)/(3,0times 10^-3)= e) 12times 10^6div 4,0times 10^3= f) -3,2times 10^16div 4,0times 10^-7= j) (6,0)/(3,0times 10^-3)= k) (8,0times 10^9)/(4,0)=
Solução

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RenataProfissional · Tutor por 6 anos
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a) 2,0\times 10^{8}\cdot 3,0\times 10^{9} = 6,0\times 10^{17}
\frac {9,0\times 10^{9}\cdot 6,0\times 10^{-6}}{3,0\times 10^{-3}} = 1,8\times 10^{14}
b) 3,5\times 10^{-15}\cdot 4,0\times 10^{5} = 1,4\times 10^{-9}
c) 8.9,0\times 10^{-19} = 8,9\times 10^{-19}
h) \frac {9,0\times 10^{9}\cdot 6,0\times 10^{-6}\cdot 2,0\times 10^{-6}}{3,0\times 10^{-5}} = 1,2\times 10^{10}
d) 2,0\times 10^{8}\cdot (-2,0\times 10^{19})\cdot (4,5\times 10^{-15}) = -1,8\times 10^{32}
i) \frac {9,0\times 10^{9}}{3,0\times 10^{-3}} = 3,0\times 10^{12}
e) 12\times 10^{6}\div 4,0\times 10^{3} = 3,0\times 10^{3}
f) -3,2\times 10^{16}\div 4,0\times 10^{-7} = -8,0\times 10^{22}
j) \frac {6,0}{3,0\times 10^{-3}} = 2,0\times 10^{3}
k) \frac {8,0\times 10^{9}}{4,0} = 2,0\times 10^{9}
\frac {9,0\times 10^{9}\cdot 6,0\times 10^{-6}}{3,0\times 10^{-3}} = 1,8\times 10^{14}
b) 3,5\times 10^{-15}\cdot 4,0\times 10^{5} = 1,4\times 10^{-9}
c) 8.9,0\times 10^{-19} = 8,9\times 10^{-19}
h) \frac {9,0\times 10^{9}\cdot 6,0\times 10^{-6}\cdot 2,0\times 10^{-6}}{3,0\times 10^{-5}} = 1,2\times 10^{10}
d) 2,0\times 10^{8}\cdot (-2,0\times 10^{19})\cdot (4,5\times 10^{-15}) = -1,8\times 10^{32}
i) \frac {9,0\times 10^{9}}{3,0\times 10^{-3}} = 3,0\times 10^{12}
e) 12\times 10^{6}\div 4,0\times 10^{3} = 3,0\times 10^{3}
f) -3,2\times 10^{16}\div 4,0\times 10^{-7} = -8,0\times 10^{22}
j) \frac {6,0}{3,0\times 10^{-3}} = 2,0\times 10^{3}
k) \frac {8,0\times 10^{9}}{4,0} = 2,0\times 10^{9}
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