Pergunta
![1. Dada as matrizes:
A=[} 3&0 -1&2 1&1 ]
Responda as somas e subtrações abaixo:
a) A+B
b) C+A
C) C+B+A
d) C-D+E
e) D+E-A](https://static.questionai.br.com/resource%2Fqaiseoimg%2F202503%2F1-dada-matrizesa-30-12-11-responda-somas-e-subtraes-tzaDYEgxet0F.jpg?x-oss-process=image/resize,w_558,h_500/quality,q_35/format,webp)
1. Dada as matrizes: A=[} 3&0 -1&2 1&1 ] Responda as somas e subtrações abaixo: a) A+B b) C+A C) C+B+A d) C-D+E e) D+E-A
Solução

4.0323 Voting

Alice MariaElite · Tutor por 8 anos
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a) A+B = [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] + [\begin{matrix} 4&-1\\ 0&2\end{matrix} ] = [\begin{matrix} 7&-1\\ -1&4\\ 1&3\end{matrix} ]
b) C+A = [\begin{matrix} 1&4&2\\ 3&1&5\end{matrix} ] + [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] = [\begin{matrix} 4&4&2\\ 2&3&7\end{matrix} ]
c) C+B+A = [\begin{matrix} 1&4&2\\ 3&1&5\end{matrix} ] + [\begin{matrix} 4&-1\\ 0&2\end{matrix} ] + [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] = [\begin{matrix} 8&2&3\\ 2&3&7\end{matrix} ]
d) C-D+E = [\begin{matrix} 1&4&2\\ 3&1&5\end{matrix} ] - [\begin{matrix} 1&5&2\\ -1&0&1\\ 3&2&4\end{matrix} ] + [\begin{matrix} 6&1&3\\ -1&1&2\\ 4&1&3\end{matrix} ] = [\begin{matrix} 6&0&3\\ 5&2&6\end{matrix} ]
e) D+E-A = [\begin{matrix} 1&5&2\\ -1&0&1\\ 3&2&4\end{matrix} ] + [\begin{matrix} 6&1&3\\ -1&1&2\\ 4&1&3\end{matrix} ] - [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] = [\begin{matrix} 6&6&8\\ 0&2&6\end{matrix} ]
b) C+A = [\begin{matrix} 1&4&2\\ 3&1&5\end{matrix} ] + [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] = [\begin{matrix} 4&4&2\\ 2&3&7\end{matrix} ]
c) C+B+A = [\begin{matrix} 1&4&2\\ 3&1&5\end{matrix} ] + [\begin{matrix} 4&-1\\ 0&2\end{matrix} ] + [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] = [\begin{matrix} 8&2&3\\ 2&3&7\end{matrix} ]
d) C-D+E = [\begin{matrix} 1&4&2\\ 3&1&5\end{matrix} ] - [\begin{matrix} 1&5&2\\ -1&0&1\\ 3&2&4\end{matrix} ] + [\begin{matrix} 6&1&3\\ -1&1&2\\ 4&1&3\end{matrix} ] = [\begin{matrix} 6&0&3\\ 5&2&6\end{matrix} ]
e) D+E-A = [\begin{matrix} 1&5&2\\ -1&0&1\\ 3&2&4\end{matrix} ] + [\begin{matrix} 6&1&3\\ -1&1&2\\ 4&1&3\end{matrix} ] - [\begin{matrix} 3&0\\ -1&2\\ 1&1\end{matrix} ] = [\begin{matrix} 6&6&8\\ 0&2&6\end{matrix} ]
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