4) (3n-4)(6n+1) A) 12n^2+6n=6 B) 12n^3=6 A j

To solve the expression $(3n-4)(6n+1)$, we need to use the distributive property of multiplication over addition.<br /><br />Step 1: Multiply the first term of the first expression with each term of the second expression.<br />$(3n-4)(6n+1) = 3n \cdot 6n + 3n \cdot 1$<br /><br />Step 2: Multiply the second term of the first expression with each term of the second expression.<br />$(3n-4)(6n+1) = -4 \cdot 6n - 4 \cdot 1$<br /><br />Step 3: Combine the like terms.<br />$(3n-4)(6n+1) = 18n^2 + 3n - 24n - 4$<br /><br />Step 4: Simplify the expression.<br />$(3n-4)(6n+1) = 18n^2 - 21n - 4$<br /><br />Therefore, the correct answer is not listed among the options provided.