(6) (4x-1)/(2)-(3x-5)/(6)= (7) (x-3y)/(6)-(3x-7y)/(10)= (8) -(x-3)/(15)+(-7x+3)/(5)= (9) ((2x+5)/(3)-(x-5)/(4))times 12= (10) 24((x-3y)/(6)-(2x+y)/(8))=

(6) $$\frac {4x-1}{2}-\frac {3x-5}{6} = \frac{6(4x-1) - 3(3x-5)}{12} = \frac{24x - 6 - 9x + 15}{12} = \frac{15x + 9}{12} = \frac{5x + 3}{4}$$

(7) $$\frac {x-3y}{6}-\frac {3x-7y}{10} = \frac{5(x-3y) - 3(3x-7y)}{30} = \frac{5x - 15y - 9x + 21y}{30} = \frac{-4x + 6y}{30} = \frac{-2x + 3y}{15}$$

(8) $$-\frac {x-3}{15}+\frac {-7x+3}{5} = \frac{-x+3}{15} + \frac{-35x+15}{15} = \frac{-36x+18}{15} = \frac{-12x+6}{5} = -\frac{12}{5}x + \frac{6}{5}$$

(9) $$(\frac {2x+5}{3}-\frac {x-5}{4})\times 12 = \frac{4(2x+5) - 3(x-5)}{12} \times 12 = \frac{8x + 20 - 3x + 15}{12} \times 12 = \frac{5x + 35}{12} \times 12 = 5x + 35$$

(10) $$24(\frac {x-3y}{6}-\frac {2x+y}{8}) = 24 \times \frac{4(x-3y) - 3(2x+y)}{48} = 24 \times \frac{4x - 12y - 6x - 3y}{48} = 24 \times \frac{-2x - 15y}{48} = -x - 5y$$