The length of a rectangle is 4 yd longer than its width. If the perimeter of the rectangle is 44 yd, find its area. [1]yd^2

## Step 1<br />The problem provides us with the perimeter of the rectangle, which is 44 yards. The formula for the perimeter of a rectangle is given by:<br />### \(P = 2L + 2W\)<br />where \(P\) is the perimeter, \(L\) is the length, and \(W\) is the width of the rectangle.<br /><br />## Step 2<br />We are also given that the length of the rectangle is 4 yards longer than its width. This can be represented as:<br />### \(L = W + 4\)<br /><br />## Step 3<br />We can substitute the expression for \(L\) from Step 2 into the perimeter formula from Step 1. This gives us:<br />### \(44 = 2(W + 4) + 2W\)<br /><br />## Step 4<br />Solving the equation from Step 3 for \(W\), we find that \(W = 12\) yards.<br /><br />## Step 5<br />Substituting \(W = 12\) into the equation \(L = W + 4\) from Step 2, we find that \(L = 16\) yards.<br /><br />## Step 6<br />The area of a rectangle is given by the formula:<br />### \(A = L * W\)<br />Substituting the values of \(L\) and \(W\) we found in Step 5, we find that the area of the rectangle is \(16 * 12 = 192\) square yards.