A line has a slope of (2)/(5) and passes through the point (-5,18) . Write its equation in slope-in itercept form. Write your an swer using integers , propel fractions, and improper in simplest form

To find the equation of the line in slope-intercept form, we can use the formula:<br /><br />$y = mx + b$<br /><br />where $m$ is the slope and $b$ is the y-intercept.<br /><br />Given that the slope is $\frac{2}{5}$ and the line passes through the point $(-5,18)$, we can substitute these values into the equation to find the y-intercept.<br /><br />Using the point $(-5,18)$, we have:<br /><br />$18 = \frac{2}{5}(-5) + b$<br /><br />Simplifying this equation, we get:<br /><br />$18 = -2 + b$<br /><br />Adding 2 to both sides, we have:<br /><br />$b = 20$<br /><br />Therefore, the equation of the line in slope-intercept form is:<br /><br />$y = \frac{2}{5}x + 20$