8) (1+frac(1)/(2))(3-(5)/(2)) cdot frac(3,5){}=

Para resolver essa expressão, vamos seguir a ordem das operações matemáticas.<br /><br />Primeiro, vamos simplificar a fração \( \frac{1+\frac{1}{2}}{3-\frac{5}{2}} \):<br /><br />\( \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} ={1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{1}{2}}{3-\frac{5}{2}} = \frac{1+\frac{