Trés alunos, X, Y e Z , estão matriculados em um curso de ingles. Para avaliar esses alunos, o professor optou por fazer cinco provas. Para que seja aprovado nesse curso, o aluno deverá ter a média aritmética das notas das cinco provas maior ou igưt Tempo restante 1:26:36 Ocular notas que cada aluno tirou em cada prova. Aluno & }(c) 1^mathrm(a) Prova & 2^mathrm(a) Prova & 3^mathrm(a) Prova & 4^mathrm(a) Prova & 5^mathrm(a) Prova mathrm(X) & 5 & 5 & 5 & 10 & 6 mathrm(Y) & 4 & 9 & 3 & 9 & 5 mathrm(Z) & 5 & 5 & 8 & 5 & 6 Com base nos dados da tabela é nas informaçōes dadas, ficará(ão) reprovado(s) Escolha uma opção: a. apenas o aluno Y . b. apenas os alunos X in Z . c. apenas os alunos X in Y . d. apenas o aluno Z .

## Step 1: Calculate the Average Score for Each Student<br />### To determine if a student passes, we need to calculate the average score of their five tests. The formula for the average is given by:<br /><br />\[<br />\text{Average} = \frac{\text{Sum of all test scores}}{\text{Number of tests}}<br />\]<br /><br />### For Student X:<br />- Scores: \(5, 5, 5, 10, 6\)<br />- Sum: \(5 + 5 + 5 + 10 + 6 = 31\)<br />- Average: \(\frac{31}{5} = 6.2\)<br /><br />### For Student Y:<br />- Scores: \(4, 9, 3, 9, 5\)<br />- Sum: \(4 + 9 + 3 + 9 + 5 = 30\)<br />- Average: \(\frac{30}{5} = 6.0\)<br /><br />### For Student Z:<br />- Scores: \(5, 5, 8, 5, 6\)<br />- Sum: \(5 + 5 + 8 + 5 + 6 = 29\)<br />- Average: \(\frac{29}{5} = 5.8\)<br /><br />## Step 2: Determine Passing Criteria<br />### According to the problem, a student must have an average score greater than or equal to 6 to pass.<br /><br />## Step 3: Evaluate Each Student Against the Passing Criteria<br />### - Student X has an average of 6.2, which is greater than 6, so they pass.<br />### - Student Y has an average of 6.0, which is equal to 6, so they pass.<br />### - Student Z has an average of 5.8, which is less than 6, so they fail.<br /><br />## Step 4: Identify the Correct Option<br />### Based on the evaluations, only Student Z fails. Therefore, the correct option is the one that states "apenas o aluno \( Z \)" (only student Z).