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2: Calcule ue valer das expressoles: a) 2^0+2^-3=(1+1)/(2)=2+1=(3)/(2) e) (2^-3) div(3^-2) b) 3^0+3^-2= f) (5^-2) div(2^-5) c) (2^-2) cdot(3^-2)= g) (6^-2) div(8^-2) d) (3^-3) cdot(4^-2)= h) 2^5+2^4-2^0

Pergunta

2: Calcule ue valer das expressoles:
a) 2^0+2^-3=(1+1)/(2)=2+1=(3)/(2) 
e) (2^-3) div(3^-2) 
b) 3^0+3^-2= 
f) (5^-2) div(2^-5) 
c) (2^-2) cdot(3^-2)= 
g) (6^-2) div(8^-2) 
d) (3^-3) cdot(4^-2)= 
h) 2^5+2^4-2^0

2: Calcule ue valer das expressoles: a) 2^0+2^-3=(1+1)/(2)=2+1=(3)/(2) e) (2^-3) div(3^-2) b) 3^0+3^-2= f) (5^-2) div(2^-5) c) (2^-2) cdot(3^-2)= g) (6^-2) div(8^-2) d) (3^-3) cdot(4^-2)= h) 2^5+2^4-2^0

Solução

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Ursula MariaElite · Tutor por 8 anos

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Vamos corrigir e calcular corretamente cada expressão:

a) 2^{0} + 2^{-3} = 1 + \frac{1}{8} = 1 + 0.125 = 1.125

b) 3^{0} + 3^{-2} = 1 + \frac{1}{9} = 1 + 0.111 = 1.111

c) \left(2^{-2}\right) \cdot \left(3^{-2}\right) = \frac{1}{4} \cdot \frac{1}{9} = \frac{1}{36}

d) \left(3^{-3}\right) \cdot \left(4^{-2}\right) = \frac{1}{27} \cdot \frac{1}{16} = \frac{1}{432}

e) \left(2^{-3}\right) \div \left(3^{-2}\right) = \frac{1}{8} \div \frac{1}{9} = \frac{1}{8} \cdot 9 = \frac{9}{8} = 1.125

f) \left(5^{-2}\right) \div \left(2^{-5}\right) = \frac{1}{25} \div \frac{1}{32} = \frac{1}{25} \cdot 32 = \frac{32}{25} = 1.28

g) \left(6^{-2}\right) \div \left(8^{-2}\right) = \frac{1}{36} \div \frac{1}{64} = \frac{1}{36} \cdot 64 = \frac{64}{36} = \frac{16}{9} = 1.777

h) 2^{5} + 2^{4} - 2^{0} = 32 + 16 - 1 = 47

Portanto, as respostas corretas são:
a) 1.125
b) 1.111
c) \frac{1}{36}
d) \frac{1}{432}
e) 1.125
f) 1.28
g) 1.777
h) 47
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