ordinate Plane - Part II Find the distance, d , of AB . A=(-2,-10)B=(-6,0) d= sqrt(|x_(2)-x_(1)|^(2)+|y_(2)-y_(1)|^(2)) d=[?] Distance ciund to the nearest tenth. Enter

<p>The distance between two points in a plane can be found using the distance formula, which is derived from the Pythagorean theorem. The distance formula is \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\), where \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of the two points. In this case, the coordinates of points A and B are \((-2, -10)\) and \((-6, 0)\) respectively. Substituting these values into the distance formula gives \(d = \sqrt{(-6 - -2)^2 + (0 - -10)^2} = 2 \sqrt{29}\).</p>