Identify an equation in slope-intercept form for the line parallel to y=5x+2 that passes through (-6,-1) A. y=-5x-11 B y=5x-29 C y=(1)/(5)x+(1)/(6) D y=5x+29

## Step 1: Identify the slope of the given line<br />The given line is in slope-intercept form, which is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. In this case, the slope of the given line is 5.<br /><br />## Step 2: Use the point-slope form to find the equation of the parallel line<br />Since the parallel line has the same slope as the given line, its slope is also 5. We can use the point-slope form of a line, which is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line. Substituting the given point \((-6, -1)\) and the slope 5, we get:<br />\[y - (-1) = 5(x - (-6))\]<br />\[y + 1 = 5(x + 6)\]<br /><br />## Step 3: Simplify the equation to slope-intercept form<br />To simplify the equation to slope-intercept form, we need to distribute the 5 on the right side of the equation and then subtract 1 from both sides:<br />\[y + 1 = 5x + 30\]<br />\[y = 5x + 29\]