Pergu ntail1p ontol As ra izes d a equa cao y^3-9y=0 sao. 3e -3 joeg 0e3 0 -9 e 9 -3 e 3

## Step 1<br />The given equation is \(y^3 - 9y = 0\). We can rewrite this equation by factoring out the common factor, which is \(y\). This gives us \(y(y^2 - 9) = 0\).<br /><br />## Step 2<br />Next, we notice that the term \(y^2 - 9\) is a difference of squares. This can be factored into \((y - 3)(y + 3)\).<br /><br />## Step 3<br />Substituting the factored form of \(y^2 - 9\) into the equation, we get \(y(y - 3)(y + 3) = 0\).<br /><br />## Step 4<br />Setting each factor equal to zero gives us the solutions for \(y\). If \(y = 0\), the equation is satisfied. If \(y - 3 = 0\), then \(y = 3\). If \(y + 3 = 0\), then \(y = -3\).