Dadas as matrizes A=([1,-1],[2,3]) e B=([0,1],[3,8]) então, calculando-se C=(A+B)^(2) , obtém-se EXATAMENTE como resultado a matriz C . Assim sendo, assinale a alternativa CORRETA. A) C=([1,0],[60,121]) B) C=([1,0],[25,121]) C) C=([1,0],[4,8])

【Explicação】: Para resolver essa questão, devemos somar as matrizes A e B para, em seguida, calcular o quadrado da matriz resultante C.<br />Matrix "A" given by <br /> 1 -1 <br /> 2 3<br /><br />Matrix "B" = <br /> 0 1<br /> 3 8<br /><br />Doing the operation of adding Matrica "A" + Matrica "B", to have matriz C<br /> Se for C = A + B onde:<br /><br /> 1+0 -1+1 <br /> 2+3 3+8 <br />So , investment C will be <br /> <br /> 1 0<br /> 5 11 <br /><br />Next we will calculate Square of C:<br />(C)^2 which results in :<br /> <br /> is a 2x2 so<br /> <br /> c[1,1] = c[1,1]*c[1,1] + c[1,2]*c[2,1] = 1*1 + 0*5 proportion C1,1= 1 <br /> c[1,2] = c[1,1]*c[1,2] + c[1,2]*c[2,2] = 1*0 + 0*11 is C1,2 =0<br /> c[2,1] = c[2,1]*c[1,1] + c[2,2]*c[2,1] = 5* 1 + 11* 5 proportion C2,1=60<br /> c[2,2] = c[2,1]*c[1,2] + c[2,2]*c[2,2] = 5 * 0 + 11 * 11 offer C2,2=121<br /> <br /><br />Now Arranging results in matrix format we will have Caviated:<br /> (C) ^ 2 = <br /> 1 0 <br /> 60 121 <br />lo in answer to the question to As opicoMoAcetarsressreaspoddl<br /> <br /> <br /><br />【Resposta】: A) C=(1 0 60 121)